Count duplicate values in array

Question

Counting values with the following code turns no results to my array. Would appreciate any help on what I did wrong thanks.

$xml=simplexml_load_file("sitemap.xml");

$arr = array();
foreach($xml->url as $child)
{
    if (isset($child->loc)) {
        echo "true";
        $arr[] = $child->loc;
    } else {
        echo "error";
        echo  $child->loc; 
    }        
}
print_r(array_count_values($arr));

Can you show var_dump($arr) and var_dump(array_count_values($arr))? — Barmar
– Barmar, Commented Sep 2, 2013 at 6:39

Ja͢ck · Accepted Answer · 2013-09-02 06:40:08Z

2

You have to cast the item values properly, otherwise you would be storing SimpleXMLElement objects in your array:

$arr[] = (string)$child->loc;

answered Sep 2, 2013 at 6:40

Ja͢ck

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Comments

Senthil · Accepted Answer · 2013-09-02 07:30:41Z

0

May be expecting like this

$xml=simplexml_load_file("sitemap.xml");

echo "<pre>";
var_dump($xml->url->loc[0]);
var_dump($xml->url->loc[1]);
var_dump($xml->url->loc[2]);

echo "</pre>";

$arr = array();

foreach($xml->url as $child)
{
    foreach($child as $tmp){    
        if (isset($tmp)) {
            echo "true";
            $arr[] = (String)$child->loc;
        } else {
            echo  "error<br/>";
            echo  $child->loc; 
        }    
    }    
}
print_r(array_count_values($arr));



<sites>
    <url>
        <loc>google.com</loc>
        <loc>google.com</loc>
        <loc>yahoo.com</loc>
    </url>
</sites>

answered Sep 2, 2013 at 7:30

Senthil

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Comments

Tonzkie · Accepted Answer · 2013-09-03 03:35:57Z

0

Solution formed after the answer of jack. Added this code to check for duplicates.

if(count($arr) != count(array_unique($arr))){
      echo "Duplicates";
   }

edited Sep 3, 2013 at 3:35

answered Sep 2, 2013 at 6:49

Tonzkie

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1 Comment

user2136840 Over a year ago

I guess that's debugging code, but if count($arr) doesn't equal count(array_unique($arr)) that means there are duplicates.

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