Converting byte array containing ASCII characters to a String

Question

I have a byte array that consists of ASCII characters that I wish to convert to a String. For example:

byte[] myByteArray = new byte[8];
for (int i=0; i<8; i++) {
    byte[i] = (byte) ('0' + i);
}

myByteArray should contain a string "12345678" after the loop. How do I get this string into a String variable?

Thanks!

rocketboy · Accepted Answer · 2013-09-03 02:41:16Z

48

Use

new String(myByteArray, "UTF-8");

String class provides a constructor for this.

Side note:The second argument here is the CharSet(byte encoding) which should be handled carefully. More here.

answered Sep 3, 2013 at 2:41

rocketboy

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1 Comment

Toby Over a year ago

If op wants to convert *from" ASCII, then shouldn't this be new String(myByteArray, "ISO-8859-1");? (Assuming 8-bit ASCII/ISO-LATIN rather rather than old 7-bit)

Java Devil · Accepted Answer · 2013-09-03 02:41:53Z

4

String aString = new String(yourByteArray);

or

String aString = new String(yourByteArray, "aCharSet"); 
//Replacing "aCharSet" with the appropriate chararacter set

Easy See docs

answered Sep 3, 2013 at 2:41

Java Devil

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1 Comment

user1118764 Over a year ago

Thanks! That worked! Just needed to add in throw/catch blocks or Eclipse will complain

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