I have a button on my page :
<button class="play"></button>
When I click on it, it launches the video via jQuery
$('.play').on('click',function(){
player.play();
});
But I also want to add PHP code to save the user ID in the database when he clicks on that button.
How can I mix PHP & jQuery? I'm not used to Ajax, is it the solution?
Thanks for your help!
add a function:
function add_to_db(user_id){
$.post('add.php', {userId: user_id}, function(response){
//do something with the response
r = JSON.parse(response);
if (r.status === 'error'){
//handle the error
alert(r.message);
}
});
});
when you play do the following
$('.play').on('click',function(){
player.play();
user_id = //however you chose to set this in the page
add_to_db(user_id);
});
your add.php:
//perform your db update or insert
//if successful:
$response['status'] = 'success';
//else:
$response['status'] = 'error';
$response['message'] = 'update was not successful';
//look into try/catch blocks for more detailed error messaging.
//then send the response back
echo json_encode($response);
' after error in the first block of code.
r = JSON.parse(response);. You can do it automatically by appending "json" after the success callback
$.post(url,data,callback,"json"); Source: api.jquery.com/jQuery.postTry using ajax
$('.play').on('click',function(){
player.play();
$.ajax({
type: "POST",
url: "some.php", // your php file name
data:{id :"id"}, //pass your user id
success:function(data)
{
if(data==true)
alert("success");
else
alert("error");
}
});
}
<?php
$success=false; //Declare and initialize a variable
// do your code to update your database
//and check if the database is updated , if so set $success=true
echo $success;
?>
success would still be displayed even though that is not entirely true.
.ajax(),.get(),.post(), whichever is easiest for you) to make a request to that server-side handler, sending it the value from the page.