jQuery error, variable is not defined

Question

I'm trying following code to create a plugin. I'm getting error at the line if(options.controls == true)

The error I get is 'options is not defined'.

How should I define it?

(function($) {

    $.fn.jwslider = function(options){
        var defaults = {            
            controls: true           
        };      
        var options = $.extend(defaults, options);      
    }

    init();

    function init()
    {
        if(options.controls == true)
        {
            alert("controls true");
        }       

    } 

}(jQuery));

options is defined only inside the $.fn.jwslider scope, you have to declare it outside and then assign it inside that function(you will need to give a new name to the parameter of the function, maybe opts) — Niccolò Campolungo
– Niccolò Campolungo, Commented Sep 7, 2013 at 19:12

jasonslyvia · Accepted Answer · 2013-09-07 19:16:24Z

1

(function($) {

    $.fn.jwslider = function(options){
        var defaults = {            
            controls: true           
        };      
        var options = $.extend(defaults, options);      

        init();

        function init()
        {
            if(options.controls == true)
            {
                alert("controls true");
            }       
        } 
    }
}(jQuery));

Then the options is accessible inside init function

answered Sep 7, 2013 at 19:16

jasonslyvia

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Comments

Rahul Tripathi · Accepted Answer · 2013-09-07 19:13:20Z

1

You have to define the options variable outside the scope of function.

Currently it is defined in the scope of $.fn.jwslider hence it is giving the error.

answered Sep 7, 2013 at 19:13

Rahul Tripathi

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