jQuery error when extending object prototype

Question

If I extend the Object prototype and try to use some functions of jQuery 2.0.3 I get errors...

Object.prototype.GetHashCode = function() { return 1; };
$(document).on("click", "div", function() { });

If I do this and then click any div I get an error

Uncaught TypeError: Object function () { return 1; } has no method 'exec'

Why does it happen? Is there a workaround or a way to fix this bug in jQuery?

possible duplicate of How to define method in javascript on Array.prototype and Object.prototype so that it doesn't appear in for in loop — Bergi
– Bergi, Commented Sep 10, 2013 at 17:05
@Chandu: OK, it doesn't exactly answer the question. Why does this happen? - because you're destroying all for in property enumerations with extending the Object.prototype. It is not a bug in jQuery. Is there a workaround? - see the linked duplicate — Bergi
– Bergi, Commented Sep 10, 2013 at 17:11
Seems like a jquery bug...by the way this works fine $('div').click(function() { console.log('div clicked'); }); — NaveenBhat
– NaveenBhat, Commented Sep 10, 2013 at 17:55
@NaveenBhat: No, it is not a jQuery bug. It is just that a for in loop is used in the code when a delegated event is triggered, but not for a directly attached handler. — Bergi
– Bergi, Commented Sep 10, 2013 at 18:26
possible duplicate of Why does this JavaScript prototype function break jQuery? — bfavaretto
– bfavaretto, Commented Sep 16, 2013 at 18:58

georg · Accepted Answer · 2013-09-10 18:36:55Z

5

In this report they say they don't want to fix that. So don't use Object.prototype when working with jquery.

answered Sep 10, 2013 at 18:36

georg

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