I'm trying to create a loop menu script and my main-while turn to false when secondary menu turn to false... what do you think that I need fix?
#!/bin/bash
function f_menu_main () {
echo "1) option1";
echo "2) option2";
echo "3) option3";
echo "4) option4";
echo "99) exit";
}
function f_case_main () {
case $selection0 in
"1" ) function1; selection0="1"; ;;
"2" ) function2; selection0="2"; ;;
"3" ) function3; selection0="3"; ;;
"4" ) f_run_app packages 1; ;;
"99" | "q" | "exit" | "quit") selection0="exitl0"; ;;
*) f_menu_main; ;;
esac
}
function f_case_packages () {
case $selection1 in
"1" ) function1; selection1="1"; ;;
"2" ) function2; selection1="2"; ;;
"99" | "q" | "exitl" | "quit") selection1="exitl1"; ;;
*) f_menu_packages; ;;
esac
}
function f_menu_packages () {
echo "1) options";
echo "2) options";
echo "99) exit";
}
function f_run_app () {
selection="selection"$2;
exitlv="exitl"$2;
while [ "${!selection}" != "$exitlv" ]; do
echo "";
f_menu_$1;
echo "Last selection: \""${!selection}" "$2"\".";
echo -n "Select a item from menu: "; read "selection"$2;
f_case_$1;
done
}
f_run_app main 0;
My supposition is when selection1 is exit1 while1 exit but while0 exit too and the variable selection0 is not exit0.
local selectionandlocal exitlvat the top off_run_app.select. gnu.org/software/bash/manual/…