putting shell_exec() output into array [duplicate]

Question

I have a line of php :

$output = shell_exec('ps aux | grep 9902 | awk \'{print $11" "$2}\'');

print $output; will give the output :

rtmpgw 10089
/usr/bin/vlc 10107
sh 10123
grep 10125

I tried using this next line to put the above output into an array.

$oparray = explode(" ", trim($output));

It works, but not as expected. print_r($oparray); will give the following output :

Array
(
    [0] => rtmpgw
    [1] => 10089
/usr/bin/vlc
    [2] => 10107
sh
    [3] => 10123
grep
    [4] => 10125
)

This confuses me as I would expect an Index number for each value but three of the values appear to be without indices.

So I suppose my question here is two parts

What is going on in the output above
Can anyone help me get a useful array that looks like this :

Array
( [0] => rtmpgw [1] => 10089 [2] => /usr/bin/vlc [3] => 10107 [4] => sh [5] => 10123 [6] => grep [7] => 10125 )

Thanks~

Jason OOO · Accepted Answer · 2013-09-24 08:32:33Z

11

Try this:

<?php
$text = 'rtmpgw 10089
/usr/bin/vlc 10107
sh 10123
grep 10125';

$oparray = preg_split("#[\r\n]+#", $text);

print_r($oparray);
?>

Array
(
    [0] => rtmpgw 10089
    [1] => /usr/bin/vlc 10107
    [2] => sh 10123
    [3] => grep 10125
)

answered Sep 24, 2013 at 8:32

Jason OOO

3,5622 gold badges28 silver badges32 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

DevOpsSauce Over a year ago

This worked perfectly, except I had to add trim() to the $text variable, like $response_array = preg_split("#[\r\n]+#", trim($output)); Otherwise, it returned an extra index.

raina77ow · Accepted Answer · 2013-09-24 08:29:39Z

10

The lines in shell_exec output are separated by the end-of-line symbol - and that's different from normal whitespace, that's why explode doesn't account for it.

You can use preg_split instead, with \s character class matching both normal whitespace and EOL.

$oparray = preg_split('/\s+/', trim($output));

answered Sep 24, 2013 at 8:29

raina77ow

107k16 gold badges205 silver badges240 bronze badges

2 Comments

BryanK Over a year ago

Perfect Array. Simple solution and works good. Thanks so much.

Ibrahim Over a year ago

this solution will not work well for output name those contains whitespace! For example a file name like Hello world , this solution will create [0]=>['Hello','world']

Kevin · Accepted Answer · 2013-09-24 08:30:27Z

1

$array = array();
foreach(preg_split("/((\r?\n)|(\r\n?))/", $subject) as $line){
    $oparray = explode(" ", trim($line));
    $array[] = $oparray[0];
    $array[] = $oparray[1];
}

answered Sep 24, 2013 at 8:30

Kevin

1,0002 gold badges10 silver badges31 bronze badges

2 Comments

andy Over a year ago

Just a pointer, you don't need to declare $array if you are using []=

Manu Over a year ago

it's true that you don't need Array(), but I often include it to make sure that the variable is empty.

Dan Bray · Accepted Answer · 2023-05-16 20:03:11Z

0

There's no need to use preg_split as this can be achieved with explode and should perform better. Output is separated using end of line characters. Simply use explode with PHP_EOL. Considering, you also wish to have items separated by spaces, you'll also need to do a str_replace.

$array = explode(PHP_EOL, str_replace(' ', PHP_EOL, $output));

If you are left with an empty string at the end of your array, use:

$array = explode(PHP_EOL, rtrim(str_replace(' ', PHP_EOL, $output)));

answered May 16, 2023 at 20:03

Dan Bray

7,9024 gold badges61 silver badges72 bronze badges

Collectives™ on Stack Overflow

putting shell_exec() output into array [duplicate]

4 Answers 4

1 Comment

2 Comments

2 Comments

Comments

Linked

Hot Network Questions

Collectives™ on Stack Overflow

4 Answers 4

1 Comment

2 Comments

2 Comments

Comments

Linked

Related