I have a Python object:
time.struct_time(tm_year=2013, tm_mon=10, tm_mday=11, tm_hour=11, tm_min=57, tm_sec=12, tm_wday=4, tm_yday=284, tm_isdst=0)
And I need to get an ISO string:
'2013-10-11T11:57:12Z'
How can I do that?
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2 Answers
Using time.strftime() is perhaps easiest:
iso = time.strftime('%Y-%m-%dT%H:%M:%SZ', timetup)
Demo:
>>> import time
>>> timetup = time.gmtime()
>>> time.strftime('%Y-%m-%dT%H:%M:%SZ', timetup)
'2013-10-11T13:31:03Z'
You can also use a datetime.datetime() object, which has a datetime.isoformat() method:
>>> from datetime import datetime
>>> datetime(*timetup[:6]).isoformat()
'2013-10-11T13:31:03'
This misses the timezone Z marker; you could just add that.
answered Oct 11, 2013 at 13:28
Martijn Pieters
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2 Comments
FObersteiner
It should be noted that this assumes that
timetup refers to UTC ('Z').
Martijn Pieters
@MrFuppes only because I used
time.gmtime() to create it; the OP didn’t show how they had created theirs. You can also use time.localtime(), but given that the expected output included a Z (UTC timezone) marker and the formatted time matched their timeup value, it was a reasonable assumption that they had used time.gmtime() to create it.iso = time.strftime('%Y-%m-%dT%H:%M:%SZ', timetup)
The last format charater ‘Z’ is not necessary, such as
iso = time.strftime('%Y-%m-%dT%H:%M:%S', timetup)
You will get time string like '2015-11-05 02:09:57'
