When I input a choice, with a couple of 'if' statements after it, all the other 'if' statements except for the first one is ignored. For example:
print('1. dostuff')
print('2. stuff')
choice = input('What do you want to do? ')
if choice == '1' or 'dostuff':
domorestuff()
if choice == '2' or 'stuff':
stuff()
Whatever I input, it will always go to 'domorestuff()'.
It should be:
if choice in ('1', 'dostuff'):
Right now, Python is reading your code like this:
if (choice == '1') or 'dostuff':
This means that it will always return True because "dostuff" will always evaluate to True since it is a non-empty string. See a demonstration below:
>>> choice = None
>>> choice == '1' or 'dostuff'
'dostuff'
>>> bool(choice == '1' or 'dostuff')
True
>>>
The solution I gave however uses the in keyword to test if choice can be found in the tuple ('1', 'dostuff').
This is a very common mistake. It should be something like:
if choice == '1' or choice == 'dostuff':
domorestuff()
if choice == '2' or choice == 'stuff':
stuff()
You need to reiterate the choice ==. As is, the condition is being seen as:
if (choice == '1') or ('dostuff'):
which will always be true, since 'dostuff' is truthy.
bool('dostuff')