php nested array to dictionary

Question

How can I get this:

(
[0] => Array
    (
        [name] => variation
        [value] => variation1
    )

[1] => Array
    (
        [name] => variationid
        [value] => 70105
    )

[2] => Array
    (
        [name] => fullName
        [value] => 
    )

[3] => Array
    (
        [name] => address
        [value] => 
    )

[4] => Array
    (
        [name] => country
        [value] => usa
    )

[5] => Array
    (
        [name] => state
        [value] => Utah
    )

to look like this:

$fields['variation']=>variation1[variationid]=>70105.. etc

I tried:

foreach($_POST['fields'] as $key => $value){
    $fields[$key] = $value;
}

I thought this should work, but it gives it back to me looking the exact same way. This is just a serializedArray() from jquery passed into POST; I basically just want to be able to access it using the $fields['variation'] accessing. But it's making it difficult.

kero · Accepted Answer · 2013-10-29 22:40:06Z

3

You aren't using the nested array correctly, $value holds the array with name and value and since $key (0,1,...) is not needed, you don't even need to define it.

foreach ($_POST['fields'] as $data) {
    $fields[ $data['name'] ] = $data['value'];
}

answered Oct 29, 2013 at 22:40

kero

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4 Comments

Gisheri Over a year ago

Thank you. That works, and it seems obvious now that you show it. As a side comment, is it possible to make jQuery send the form data as a one level array into post, just as the browser would? Instead of having to fix it like this in php once you receive it?

kero Over a year ago

That should be no problem but depends on how exactly you use jQuery to send a POST request

Gisheri Over a year ago

<form class=myform> <input type=hidden name=variationid value=70105/> <input name=fullName value=myname/> etc.. $form = $('#myForm'); $fields = $form.serializeArray(); $.post("handler.php", "fields": $fields); Sorry i don't know how to put line breaks in... @kingkero

kero Over a year ago

Ah ok, I honestly don't know if you can do this without ending up writing your own JS method. Research this topic and (if you didn't find a solution) ask another question on SO ;)

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