php function: number_format()

Question

$result = number_format($x, 2, '.', ','); //Will do the following correctly
115255 = 115,225.00
115255.4 = 115,225.40
115255.40 = 115,225.40
115255.455 = 115,255.46

But I need when the user enters more than 2 digits after the decimal, not to cut them into 2 decimals only and to use it as it is...

115255.455 = 115,255.455
115255.4557 = 115,255.4557

Can I do something like that?

if($x == number_format($x, 3)) //I will do it in while loop later, lets test 3 now
    $result = number_format($x, 3, '.', ',');
else $result = number_format($x, 2, '.', ',');

The previous if condition never works, else only works

Hm, why you just dont separate the number and format only the integer, and then append the fraction — bksi
– bksi, Commented Nov 9, 2013 at 5:04

bksi · Accepted Answer · 2013-11-09 05:07:50Z

1

One not traditional way to do this:

$parts = explode(".", $x);
$integerPart = number_format($parts[0], 0, '', ',');
$result = $integerPart.".".$parts[1];

answered Nov 9, 2013 at 5:07

bksi

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2 Comments

Ahmed Over a year ago

yup, if it's possible :)

Ahmed Over a year ago

can I explode it to use it like $parts[0]

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