PHP Explode function. If function

Question

Could someone help suggest in below php explode function, we are displaying script after 5th listing. How is it possible to display script exactly after 5th listing and 10th listing on a page which has more than 10 listings

We tried using

if ($i == 5 & $i== 10)

but it does not work

Below is original code - which displays script after 5th listing

   <?php
  $listings = explode("<hr/>", $list);
  $numberOfListings = count($listings);
  for($i = 0; $i < $numberOfListings; ++$i) 
    {
    if ($i == 5) 
    { ?> 

   <script>  </script>

    <?php }
    echo $listings[$i] . "<hr/>";
    }
    ?>

Edit How is it like - if have to display a separate script on $i==9, could you advise.

if ($i == 4 || $i== 9) <== use this or start your itetration with $i=1 — Prince Singh
– Prince Singh, Commented Nov 11, 2013 at 5:15

Glorfindel · Accepted Answer · 2019-09-08 19:12:02Z

2

Because $i starts at 0 (0 to 9 is 10, whilst 0 to 10 is 11). Try if ($i == 4 || $i== 9), with an or operator.

Also I would not use the && (the and operator), because it is unlikely $i will ever equal both 4 and 9. I'd suggest you read into Truth Tables (and maybe Propositional Calculus) because from seeing what you had tried originally, it would be helpful to understand how a truth table works.

_{(source: wlc.edu)}

edited Sep 8, 2019 at 19:12

Glorfindel

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answered Nov 11, 2013 at 5:13

classicjonesynz

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2 Comments

Ruchika Over a year ago

thnx it works and thnx for reference url too. i will go through it

Ruchika Over a year ago

Hello, Just a small help.. How is it like - if have to display a separate script on $i=9, could you advise. Am sorryo to not have asked that in first instance. Many thanks

Krish R · Accepted Answer · 2013-11-11 05:24:55Z

0

You can use the contine, continue is used within looping structures to skip the rest of the current loop iteration and continue execution at the condition evaluation and then the beginning of the next iteration.

                $arr = range(0,9);
                foreach($arr as $number) {
                    if($number < 5) {
                        continue;
                    }
                    print $number;
                }

Ref: http://php.net/manual/en/control-structures.continue.php

edited Nov 11, 2013 at 5:24

answered Nov 11, 2013 at 5:18

Krish R

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Comments

Deepika Janiyani · Accepted Answer · 2013-11-11 06:18:47Z

0

Try using modulus operator

$listings = explode("<hr/>", $list);
$numberOfListings = count($listings);


for($i = 1; $i < $numberOfListings; ++$i)
    {
    if ($i%5 == 0)
    {
        echo "in";
        ?>
        <script>  </script>
    <?php
    }
    echo $listings[$i-1] . "<hr/>";
}

Here we are looping from 1 and there for $i <= $numberOfListings and while listing we will use $listings[$i-1]

DEMO CODE AT http://codepad.viper-7.com/lrTOgP

edited Nov 11, 2013 at 6:18

answered Nov 11, 2013 at 5:23

Deepika Janiyani

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