how to extract numbers from string using Javascript? Test cases below:
string s = 1AA11111
string s1= 2111CA2
string s result = 111111
string s1 result = 211112
My code below is not working:
var j = 0;
var startPlateNums = "";
while (j <= iStartLength && !isNaN(iStartNumber.substring(j, j + 1))){
startPlateNums = startPlateNums + iStartNumber.substring(j, j + 1);
j++;
}
How about a simple regexp
s.replace(/[^\d]/g, '')
or as stated in the comments
s.replace(/\D/g, '')
/\D/g. Saves 1 character!
You could do: EDITED:
var num = "123asas2342a".match(/[\d]+/g)
console.log(num);
// THIS SHOULD PRINT ["123","2342"]
"123asas2342a".match(/\d+/g) # => ["123", "2342"], but +1 for matching and not just replacing everything that's not a number with an empty string ''
('...'.match(/\d+/g) || []).join('') just in case there are no digitsA regex replace would probably the easiest and best way to do it:
'2111CA2'.replace(/\D/g, '');
However here's another alternative without using regular expressions:
var s = [].filter.call('2111CA2', function (char) {
return !isNaN(+char);
}).join('');
Or with a simple for loop:
var input = '2111CA2',
i = 0,
len = input.length,
nums = [],
num;
for (; i < len; i++) {
num = +input[i];
!isNaN(num) && nums.push(num);
}
console.log(nums.join(''));
iStartLengthinitialized to ? Also, what isiStartNumber?whileloop will break as soon as a non-number is encountered (isNaNbecomestrue). Looking at your sample input and output, that's not what you want. You probably want to move that condition into anifblock inside your loop.