I am working on a project that requires that I make an array of a certain structure type. The structure looks like this:
typedef struct
{
char array[30];
int num;
}structure
I have declared an array of these structures like this:
structure struct1[5];
I passed this structure array to a function which fills the first four elements with a string and a number. The fifth is left blank. Later in the program, I pass the array again and try to set the string in the structure to a user determined string using gets(). I am getting this error:
438:19: error: incompatible types when assigning to type 'char[30]' from type 'char *'
If I need to provide more clarification, please tell me.
Thanks!
EDIT: Here is what I am doing:
typedef struct
{
char array[30];
int num;
}structure;
void fillStructs(structure[]);
void userEditStructs(structure[]);
main()
{
structure myStructs[5];
fillStructs(myStructs);
userEditStructs(myStructs);
return 0;
}
void fillStructs(structure s[])
{
//code to fill myStructs elements 0-3.
}
void userEditStructs(structure s[])
{
char newArr[30];
int newNum;
printf("Please enter your string:\n\nEntry:\t");
gets(newArr);
printf("Please enter your number:\n\nEntry:\t");
scanf("%i", newNum);
s[5].array = newArr;
s[5].num = newNum;
}
gets(). It is dangerous, it is deprecated, it is removed from C++ and should be removed from C too.