Passing value to JS with php return?

Question

I have a php method that should return some values as JSON :

function pass_value() {
 .... 
 $output[] = 'some value';
 ...

 if() { 
  //JS get it right
  echo json_encode(array('response' => $output));
  return;
 }
 ...
 //eventually another echo 

}

Where's the problem to do it like this ?

function pass_value() {
 .... 
 $output[] = 'some value';
 ...

 //js doesn't get it ?
 return json_encode(array('response' => $output)); 
}

I want to terminate the other part of the method after it passes the array, but seems that JS doesn't get the JSON when it's not echoed.

Bart Friederichs · Accepted Answer · 2013-11-28 08:03:29Z

1

That's because if you do not echo, the server never sends it to the client and the JavaScript never sees it. Remember, PHP is server-side, JavaScript is client-side.

You can of course do this with the last function:

echo pass_value();

answered Nov 28, 2013 at 8:03

Bart Friederichs

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2 Comments

Bor Over a year ago

So my original solution appears to be fine ? Echoing sequenced by return statement ?

Bart Friederichs Over a year ago

@Borislav yes. But you can try that out for yourself and find out.

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