How would I give a variable a random value in javascript?
I can do this:
var myMake = ["Chevy","Subaru","Kia","Honda","Toyota"];
var x = Math.floor(Math.random() * 4 + 1);
var rand = myMake[x];
alert(rand);
which gets the desired effect, giving the variable rand a random value of one of these:
Chevy, Subaru, Kia, Honda, Toyota
but would there be a way to make a function/method that does something like this?:
var rand = randVal("Chevy", "Subaru", "Kia", "Honda", "Toyota");
Thanks!!
function randVal(){
var x = Math.floor(Math.random() * arguments.length);
return arguments[x];
}
the arguments is an array like object that refers gives a list of all supplied arguments to a function.
arguments coming from?
Just to be different!
var x = ["Chevy","Subaru","Kia","Honda","Toyota"].sort(function() {
return 0.5 - Math.random();
})[0];
alert(x);
And as a function, but accepting an Array
var randMe = function ( me ) {
if ( me ) {
return me.sort(function() {
return 0.5 - Math.random();
})[0];
}
}
alert(randMe(['a','b','c']));
And some prototyping as well
Array.prototype.rand = function() {
return this.sort(function() {
return 0.5 - Math.random();
})[0];
}
alert(['a','b','c'].rand());
Also the actual shuffle function from here.
sliceing that also ... I didn't notice that first ... but thank you anyways!You can do that very easy with jQuery:
(function($) {
$.rand = function(arg) {
if ($.isArray(arg)) {
return arg[$.rand(arg.length)];
} else if (typeof arg === "number") {
return Math.floor(Math.random() * arg);
} else {
return 4; // chosen by fair dice roll
}
};
})(jQuery);
var items = ["Chevy","Subaru","Kia","Honda","Toyota"];
var item = $.rand(items);
