I want to call a php script inside shell script and need to send 4 parameters.I called that called that inside shellscript like this.
php /var/www/php/myscript.php $var1 $var2 $var3 $var4
but php script didn't execute. so what is the correct way to send parameters to php script and execute script inside shellscript?
Suppose you have an executable file file.sh:
#!/usr/bin/php
<?php
include('your/file.php');
exit;
or with the current environment
#!/usr/bin/env php
<?php
include('your/file.php');
exit;
Then execute it on the command line with
$ ./file.sh
This is sample, pay special attention to the quotes in the parameters to wrap any character in the string like spaces or dashes that can affect the args reading.
bash.sh
#!/bin/bash
php test.php "$1" "$2"
test.php
<?php
$a = $argv[1];
$b = $argv[2];
echo "arg1 : $a, arg2: $b";
Some Outputs
$bash bash.sh Hello World
arg1 : Hello, arg2: World
$bash bash.sh Hello
arg1 : Hello, arg2:
$bash bash.sh "Hello World"
arg1 : Hello World, arg2:
Hope this helps
