This is the code I am trying to use to display information from multiple MySQL tables in one table. I'm also trying to create an else clause if the table information doesn't exist. This is my failed attempt at it.
I keep editing this as I peck away at it but at this point I still can't get it to display the final else when the row doesn't exist.
<?
include"db.inc.php";//database connection
$item = "SELECT * FROM Item";
$result = mysql_query($item);
while ($row=mysql_fetch_array($result)) // Display information from Item Table.
{
echo ("<tr><td><a href=\"edit_item.php?id=$row[ItemID]\" target=\"_blank\">Edit</a></td>");
echo ("<td>$row[ItemID]</td>");
echo ("<td>$row[Category]</td>");
echo ("<td>$row[Cost]</td>");
echo ("<td>$row[Condition]</td>");
echo ("<td>$row[PurchaseLot_PurchaseLotID]</td>");
echo ("<td>$row[Location]</td>");
echo ("<td>$row[Date]</td>");
echo ("<td>$row[Desc]</td>");
echo ("<td>$row[Notes]</td>");
echo ("<td><a href=\"photo_upload.php?id=$row[ItemID]\" target=\"_blank\">Pics</a></td>");
echo ("<td><a href=\"item_info.php?id=$row[ItemID]\" target=\"_blank\">Info</a></td></tr>");
$info = "SELECT * FROM Info WHERE Item_ItemID = $row[ItemID] ";
$info_results = mysql_query($info);
while ($info_row = mysql_fetch_array($info_results))
{
if ($info_row['Item_ItemID'] = $row['ItemID']) // Display Information from Info table If column exists with same ItemID.
{
echo ("<tr><td colspan=\"12\">");
echo ("Manufacturer:$info_row[Manufacturer]<br>");
echo ("Model:$info_row[Model]<br>");
echo ("Model Number:$info_row[ModelNumber]<br>");
echo ("Serial Number:$info_row[SerialNumber]<br>");
echo ("Service Number:$info_row[ServiceNumber]<br>");
echo ("</td></tr>");
} else //else dispaly Add information to info link.
{
echo ("<tr><td colspan=\"12\"><a href=\"item_info.php?id=$row[ItemID]\" target=\"_blank\">Add Extra Information</a></td></tr>");
}
}
}
?>