How do I find an object by object inside a javascript array

Question

I'm storing websocket connections inside an array. These are objects. And I'd like to remove a connection from the array when the connection is closed.

Is there any way I can find which connection object matches the closing connection and unset it?

I don't think indexOf works, right? Because the value is an object...

.........................................

here's some code

var connections = [];

websocketServer.on('request', function(request) {
  var connection = request.accept(null, request.origin);

  connection.on('message', function(message){
    if(message.type !== 'utf8')
      return;

    var msg = JSON.parse(message.utf8Data);

    if(msg.txt == 'something'){
      connections.push(connection);
    }

  });

  connection.on('close', function(connection) {
    // here remove connection object from connections array

  });
});

if object1 == object2 ... but i need to somehow match the exact instance — thelolcat
– thelolcat, Commented Dec 22, 2013 at 2:27
indexOf can find a specific instance of the object inside an array that contains multiple objects of the same type? — thelolcat
– thelolcat, Commented Dec 22, 2013 at 2:28
@thelolcat are you saying you want to look through the array to find objects with a closed connection or you have an object whose connection is known to be closed -- if so, how? — Explosion Pills
– Explosion Pills, Commented Dec 22, 2013 at 2:29

Joseph · Accepted Answer · 2013-12-22 02:34:49Z

1

You can do indexOf then splice

var index = connections.indexOf(connection);
if(~index) connections.splice(index,1);

answered Dec 22, 2013 at 2:34

Joseph

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2 Comments

elclanrs Over a year ago

You can just do ~index in an if.

Joseph Over a year ago

@elclanrs meant to do that :D

Shamsudheen TK · Accepted Answer · 2013-12-22 02:40:56Z

0

Use underscore.js and call _.isEqual(object, other);

Underscore is a utility-belt library for JavaScript that provides a lot of the functional programming support that you would expect in Prototype.js (or Ruby), but without extending any of the built-in JavaScript objects. It's the tie to go along with jQuery's tux, and Backbone.js's suspenders.

edited Dec 22, 2013 at 2:40

answered Dec 22, 2013 at 2:35

Shamsudheen TK

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