getting undefined index error in php

Question

I just want receive the array and print it which is sent by jquery.post()

my HTML-JS

<input type="submit"  id="myButton" />

<script type="text/javascript">

    var arr = new Array();
    arr[0] = "Ding";
    arr[1] = "Dong";
    arr[2] = "Bong";

    var json_string= JSON.stringify(arr); // convert it into a json string. 

    //and sending the data to server. temp.php.
    $("#myButton").click(function(){
    $.post('temp.php' , {json : json_string },function(data){

                       location.href = "temp.php";
         }); 

    });

</script>

I have checked by alert() that data sending is successful. After button click page is also redirecting to temp.php

My php page temp.php

<?php
    $json_string = $_POST['json']; //geting the post request. //this is line 3
    $array_items = json_decode($json_string); //converting json string to a php array.
    echo $array_items[0]; //just to print 1st element of array
 ?>

It should print Ding. But I am getting error

Undefined index: json in C:\wamp\www\phpJSarray\temp.php on line 3

What is my mistake in temp.php page ? Please help me out.

"my HTML-JS" which is completed commented out in your question, btw. — Funk Forty Niner
– Funk Forty Niner, Commented Dec 27, 2013 at 1:16
in your temp.php you should add some debug code to make sure you are getting what you think you should. on line 4 you could print $json_string; and if that's good, on line 6 try print_r($array_items); to see if you have an array with expected values. — Joe T
– Joe T, Commented Dec 27, 2013 at 1:16
Where is your form and PHP? Since you're using $json_string = $_POST['json']; The possibilities of an error are rather broad without seeing full codes. Is there not a named element such as name="json" ? — Funk Forty Niner
– Funk Forty Niner, Commented Dec 27, 2013 at 1:16
Did you check the network tab of your javascript console / firebug? Does the data get sent properly? — sk1p
– sk1p, Commented Dec 27, 2013 at 1:19

score 4 · Accepted Answer · 2013-12-27 02:17:50Z

4

call this javascript on your onclick or on form submit however u like.

var arr = new Array();
arr[0] = "Ding";
arr[1] = "Dong";
arr[2] = "Bong";

var json_string = JSON.stringify(arr); // convert it into a json string.
$("#data").val(json_string);    
$("#form1").submit(); //and sending the data to server. temp.php.

HTML:

<form action="temp.php" id="form1" method="POST">
    <input type="hidden" id="data" name="data">
</form>

temp.php

$dataArray = json_decode($_POST['data']);

edited Dec 27, 2013 at 2:17

answered Dec 27, 2013 at 2:10

user1625871

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1 Comment

JAL Over a year ago

@demo_Ashif if this post solved your question, please click the checkbox to mark it as accepted.

JAL · Accepted Answer · 2013-12-27 01:22:54Z

2

The $.post is doing an AJAX call on the current page... which has no apparent effect because once it finishes, the location.href = "temp.php"; is redirecting you to temp.php.

If you'd like to make a POST to temp.php, you could just do it through a normal form. Use jQuery to set the value of a hidden input element to json_string if desired (or better, let jQuery change the form data to JSON).

answered Dec 27, 2013 at 1:22

JAL

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Comments

Jarrod · Accepted Answer · 2013-12-27 02:16:39Z

2

<script>

$(document).ready(function() {    
   $("#myButton").on( 'click', function () {
    $.ajax({
        type: 'post',
        url: 'temp.php',
        data: {
            arr1: "Ding",
            arr2: "Dong",
            arr3: "Bong",
        },
        success: function( data ) {
            console.log( data );
        }
    });
});
});

</script>

You'd then call it by doing $_POST['arr1'];. I hope this solves your problem.

edited Dec 27, 2013 at 2:16

answered Dec 27, 2013 at 1:18

Jarrod

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7 Comments

demo_Ashif Over a year ago

json_string is alrdy encoded in json. I am calling the sent post request of json. And later decode is as php array. Btw i have tried with $_POST['json_string']. And same error

demo_Ashif Over a year ago

mistake is in my javascript code. but i am not getting any idea to solve it. Plz check if you can.

demo_Ashif Over a year ago

your code is ok and geting success alert. now what should i do to print the array data in temp.php page. Now i am reloading temp.php but not getting any data.

demo_Ashif Over a year ago

i just want print the sent array data in temp.php page

Jarrod Over a year ago

So you don't want to do anything with it like store it anywhere? Because the code that I written doesn't actually let you see it anywhere, it will just post the data to that page, it doesn't actually take you to it, therefore you can only store it in a database, write it to somewhere, etc.

|

reafle · Accepted Answer · 2013-12-27 01:23:58Z

0

After you send your data via AJAX to temp.php and it returns a successful response, redirect to temp.php with an empty POST happens. Thats why you get no data after redirect.

You should also check whether array element exists in temp.php:

<?php

    if (isset($_POST['json'])) {
        $json_string = $_POST['json']; 
        $array_items = json_decode($json_string); 
        echo $array_items[0]; 
    }

?>

answered Dec 27, 2013 at 1:23

reafle

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