PHP if function has an error

Question

I have a line in my PHP code that looks like this (it calls a function):

$objTest->joinServer($servers[array_rand($servers)]);

However, sometimes, the function/line throws back an error that continues in an infinite loop. How can I detect if this line throws back an error, and so something else instead?

Currently, I think that I may need to do something like this, but I have no idea how to implement it correctly:

$conn = $objTest->joinServer($servers[array_rand($servers)]);

if($conn has some error) {
    // Do this
} else {
    // No error so excute line
    $objTest->joinServer($servers[array_rand($servers)]);
}

Leonardo · Accepted Answer · 2013-12-27 18:32:17Z

1

try{
    $conn = $objTest->joinServer($servers[array_rand($servers)]);
catch(Exception e) {
    //do something else here
}

If an error occurs calling that function, you can output the error with: e->getMessage() or 'do something else' as you said. Read the docs: http://www.php.net/manual/en/language.exceptions.php

answered Dec 27, 2013 at 18:32

Leonardo

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2 Comments

user2898075 Over a year ago

I'm still getting the error. However, the error I'm getting is a Notice message, does that matter?

Leonardo Over a year ago

@user2898075 that's the point, since you are catching the error... what is the message?

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