How to set Javascript variable to php in Yii framework

Question

Let me know to how to set Javascript variable "ad_field_id" to $form's hidden field in php. If its set successfully the save in DB process will be handled in MyController.php class

     <?php $form=$this->beginWidget('CActiveForm', array(
          'id'=>'tab-form-123',             
          'enableAjaxValidation' => false,
              'enableClientValidation' => true,
          'stateful' => true,
              'htmlOptions' => array ('enctype' => 'multipart/form-data'),
     )); ?>

       <?php echo $form->hiddenField($model, 'ad_field_id'); ?>
       <?php echo $form::submitButton('Save',array('submit'=>'BCFormFields')); ?>

    <?php $this->endWidget();?>


    <script src="<?php echo Yii::app()->request->baseUrl; ?>/js/yui-min.js"></script>
    <script>
    Y.DD.DDM.on('drag:drophit', function(e) {
    var drop = e.drop.get('node'),
        drag = e.drag.get('node');

    var ad_field_id = ['id: ' + e.drag.get('node').get('id')];        
    }
    </script>

var ad_field_id = ['id: ' + e.drag.get('node').get('id')]; this ad_field is to be hidden field.i tried this code but it could not post in controller — Bala
– Bala, Commented Jan 6, 2014 at 11:44
i need to set/pass JS variable ad_field_id to <?php echo $form->hiddenField($model, 'ad_field_id'); ?>. Pls help to achieve this — Bala
– Bala, Commented Jan 6, 2014 at 11:55
document.getElementsByName('ad_field_id').value=ad_field_id; when i alert this statement , the variable is set properly i expected. but in controller var_dump($_POST) displays ad_field_id as null — Bala
– Bala, Commented Jan 6, 2014 at 12:51

aggelgian · Accepted Answer · 2014-01-06 13:09:08Z

1

Add an id to the hidden form element

<?php echo $form->hiddenField($model, 'ad_field_id', array('id' => 'frm_id')); ?>

then you can update your script to

var ad_field_id = ['id: ' + e.drag.get('node').get('id')];
document.getElementById('frm_id').value = ad_field_id;

answered Jan 6, 2014 at 13:09

aggelgian

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