I am new to working with Regexs in C# .NET. Say I have a string as follows...
"Working on log #4"
And within this string we can expect to see the number (4) vary. How can I use a Regex to extract only that number from the string.
I want to make sure that the string matches the first part:
"Working on log #"
And then exctract the integer from it.
Also - I know that I could do this using string.Split(), or .Substring, etc. I just wanted to know how I might use regex's to do this.
Thanks!
"Working on log #(\d+)"
The () create a match group, so you will be able to extract that section.
The \d matches any digit.
The + says "look at the previous token, match it one or more times" so it will make it match one or more digits.
So overall you're capturing a group containing one or more digits, where that group comes after "Working on log #"
`, so use \\d`.RegEx rgx = new RegEx("Working on log #[0-9]"); is the pattern you want to use. The first part is a string literal, [0-9] says that character can be any value 0 through 9. If you allow multiple digits then change it to [0-9]{x} where x is the number of repetitions or [0-9]+ as a + after any character means 1 or more of that character is allowed.
You could also just do string.StartsWith("Working on log #") then split on # and use int.TryParse() with the second value to confirm it is in fact a valid integer.
Try this: ^(?<=Working on log #)\d+$. This only captures the number. No need for a capture group. Remove ^ and $ if this is within a larger string.
^ - start of string(?<=) - positive lookbehind - ensures what is between = and ) is found before\d+ - at least one digit$ - end of stringA capturing group is the solution:
"Working on log #(?<Number>[0-9]+)"
Then you can access the matched groups using the Match.Groups property.
