If I have the following arr = [13,12,31,31] Now say I want to push in another set of numbers like 12,13,54,32
So I can do arr << [12,13,54,32] but now I have [13,12,31,31,[12,13,54,32]]
So how can I remove the outside array? arr = arr.pop works sometimes but I'm guessing that a better way exists. Please enlighten.
Don't use <<, use +
arr = [13,12,31,31]
arr += [12,13,54,32]
# arr => [13,12,31,31,12,13,54,32]
You should use Array#flatten
[[13,12,31,31,12,13,54,32]].flatten # => [13, 12, 31, 31, 12, 13, 54, 32]
You have a couple options. You could join your arrays using the + operator and not have to deal with the outer array. If you have an outer array and want to flatten it, simply call flatten on the array. As matt mentioned in the comments above, you can also use concat.
# Creates a new array
[13,12,31,31] + [12,13,54,32]
=> [13, 12, 31, 31, 12, 13, 54, 32]
# Creates a new array, unless you use flatten!
[13, 12, 31, 31, [12, 13, 54, 32]].flatten
=> [13, 12, 31, 31, 12, 13, 54, 32]
# Modifies the original array
[13,12,31,31].concat([12,13,54,32])
=> [13, 12, 31, 31, 12, 13, 54, 32]
arr << [12,13,54,32]would result in[13, 12, 31, 31, [12, 13, 54, 32]], not[[13,12,31,31,12,13,54,32]]. Is that just a typo?