$arr = array('id1','id2',...);
How to get #id1,#id2,.. from the above array?
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3 Answers
$arr = array('id1', 'id2', ...);
$ids = '#' . join(',#', $arr);
echo $ids; // => #id1,#id2,...
6 Comments
Doug Neiner
Love it... so short, but exactly on target. +1
Alix Axel
@Doug: Make it even shorter:
'#' . join(',#', $arr);.Doug Neiner
@Alix True. I always use
implode though because it parallels explode. Since split is deprecated, it seems weird to me to use join and explode together.
Jordan Running
Oh, fair enough. For some reason I thought that since 'split' is deprecated then so is 'join,' but I that was silly of me. I've updated my answer, thanks.
Alix Axel
@Jordan: I always use
implode() too, I was just adding an emphasis on Doug comment. =) |
$arr[0];
$arr[1];
The code you just provided is the same as
$arr = array(
0 => "id1",
1 => "id2");
In order to make a list of ids in CSS
$string = '';
foreach($arr as $id)
{
$string .= "#" . $id . " ";
}
3 Comments
zombat
+1 for covering both possible interpretations of an ambiguous question.
Tyler Carter
Yeah, read it wrong the first time. Thought he was asking how to access them period.
animuson
Just because he used id1 and id2 doesn't mean every ID will begin with id and end with a number, those are just examples. They could be IDs such as 'harp1', 'mem1', and 'gut2', completely irrelevant of each other.
you can iterate the array
foreach ($arr as $k){
print "#".$k."\n";
}
each "$k" is your array items
