Converting Integer to Character in Java

Question

I have this program in which in the Switch statement structure, I've calculated an expression and want to pass its result to the stack (which I have implemented in Chars). Now the problem is that I have used

            char c;
            int C = 0;
            switch(op)
            {
                case '+':
                {
                    C = B + A;
                    c = (char) C;
                    push(c);
                    break;
                }
                case '-':
                {
                    C = B - A;
                    c = (char) C;
                    push(c);
                    break;
                }
                case '*':
                {
                    C = B * A;
                    c = (char) C;
                    push(c);
                    break;
                }
                case '/':
                {
                    C = B / A;
                    c = (char) C;
                    push(c);
                    break;
                }

            }

Now if I print C (which is Integer), it would work just fine, but if I print c (which is char) or I push it to the stack, whatsoever, it would display nothing but empty. I have also used the System.out.println(C) and found out that the calculation ( C = B + A etc) works just fine but the conversion to char (c = (char) C ) does not convert the value.

Any alternative solution would be really helpful. Thanks!

For what values of A and B? or more so what is the value of C that you are trying to print? are you trying to print the number of the character value of that number? — Java Devil
– Java Devil, Commented Jan 28, 2014 at 19:01
The values of A and B are 2 and 3 respectively. The result should be according to the op which is either +, -, * or /. The variable C (integer) stores the result accurately but I am not able to convert this integer value (C) into char value(c) — user3226056
– user3226056, Commented Jan 28, 2014 at 19:03
Go the other way when printing, so that you're not trying to print out ASCII 2 or 3 (which aren't printable). System.out.println("" + ((int) c)); or anything like that, that converts your char to an int first. — Paul Hicks
– Paul Hicks, Commented Jan 28, 2014 at 19:08

Java Devil · Accepted Answer · 2014-01-28 19:08:06Z

4

You are trying to print the numerical value of C i.e. for the case 2 + 3 and want to print 5, but when doing the cast of (char) 5 you get the control character ENQ (See ASCII Characters) which will most likely not be printable by the console.

As given in another answer try

Character.forDigit(C, 10)

But this will only work for single digit answers. If more digits are required you might want to use a string and try

String.valueOf(C)

answered Jan 28, 2014 at 19:08

Java Devil

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2 Comments

Alessio Over a year ago

you are right, I didn't post the String.valueOf(C) because he said that he has a stack of char, so I think that he should know that the result must be a single-digit integer

Java Devil Over a year ago

@Alessio Yeah I noticed that too. Question looks like part of some form of calculator so I'm hope the OP is aware of any multi-digit possibilities. which could come about very easily, especially with *

Alessio · Accepted Answer · 2014-01-28 19:00:30Z

3

Character.forDigit(C, 10)

Try this, it should work.

edited Jan 28, 2014 at 19:00

answered Jan 28, 2014 at 18:55

Alessio

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1 Comment

user3226056 Over a year ago

I did that and it said that the the types are incompatible i.e. Required: char, whereas Found: Char[]

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