Ruby on Rails, Using sort on each do

Question

I'm trying to use sort on each do. I get the error

wrong number of arguments(1 for 0)

I understand that I cannot daisy chain them together. Does anyone know another methods of getting this done.

  <% Category.sort(:id).limit(4).each do |type| %>
      <%= type.name %>
  <% end %>

The result I am aiming for is to have all categories listed from a to z.

If Category is an ActiveRecord model, you want .order(:id).limit(4). — user229044
– user229044 ♦, Commented Jan 29, 2014 at 5:07
@meagar, Thanks alot. I actually did try .order but I used id instead of :id. Thanks. — Lesly Revenge
– Lesly Revenge, Commented Jan 29, 2014 at 5:21

Pavan · Accepted Answer · 2014-01-29 05:24:31Z

14

Assuming the Category is an Active Record then

<% Category.order(:id).limit(4).each do |type| %> would do the trick.

answered Jan 29, 2014 at 5:24

Pavan

33.6k8 gold badges53 silver badges78 bronze badges

Sign up to request clarification or add additional context in comments.

4 Comments

Lesly Revenge Over a year ago

thanks. But if you look under the comments, you will notice you provide the same answer as meagar

Pavan Over a year ago

oh,I didn't notice that.

Tasos Anesiadis Over a year ago

@Pavan What does the .limit(4) do here? And how do I do the sorting desceding?

inmydelorean Over a year ago

@TasosAnesiadis It's been a while but maybe this will help someone else. .limit(4) shows only 4 last records from the query result. You can use .order("created_at desc"). Replace created at with whatever you want to take into account for sorting.

Collectives™ on Stack Overflow

Ruby on Rails, Using sort on each do

1 Answer 1

4 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

4 Comments

Your Answer

Sign up or log in

Post as a guest

Related