Bash input for multiple file

Question

I have thousands of two set of files one with name.ext and another files name ending with name.ext.in, so for every name.ext there is a name.ext.in and now i have to pass this as argument to a script such as customise.pl name.ext name.ext.in. I am doing like

#!/bin/bash 

FILE1=$.ext
FILE2=$.ext.in

customise.pl $FILE1 $FILE2

but no success. Any idea?

You surely have to loop through the list of files, in order to run your customise.pl for each pair. — Rubens
– Rubens, Commented Feb 2, 2014 at 19:56

tzunghaor · Accepted Answer · 2014-02-02 20:02:56Z

4

for i in *.ext; do 
    customise.pl "$i" "$i.in"
done

edited Feb 2, 2014 at 20:02

answered Feb 2, 2014 at 19:56

tzunghaor

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1 Comment

Dolda2000 Over a year ago

Just in case there is whitespace in any of the filenames, it is probably a better idea to do customise.pl "$i" "$i.in".

Dolda2000 · Accepted Answer · 2014-02-02 20:36:49Z

2

Judging from the comments to the other answers, you probably want something like this:

for file in *.ext; do
    customise.pl "$file" "${file%.*}.new.psl"
done

The ${file%.*} syntax substitutes only the part of $file up until its last dot. You can check the manpages for Bash or Dash for more information on it if you need.

answered Feb 2, 2014 at 20:36

Dolda2000

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Comments

twin · Accepted Answer · 2014-02-02 19:57:50Z

0

If you want to run customise.pl for each pair of files, you can do it like this in a bash script:

#!/bin/bash

for i in `ls *.ext`
do
  customise.pl $i $i.in
done

answered Feb 2, 2014 at 19:57

twin

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3 Comments

Dolda2000 Over a year ago

for i in $(ls *.ext) has the problem that it doesn't deal with whitespace and quoting properly. for i in *.ext works better.

user3263699 Over a year ago

if it is like name.ext and the second file is like name.XYZ.in where XYZ is a common in the header of the second file.

user3263699 Over a year ago

Hi thanks, but the problem is that only name is similar I have thousands of two set of files one with name.ext and another files for the same name ending with name.new.psl, so for every name.ext there is a name.new.psl and now i have to pass this as argument to a script such as customise.pl name.ext name.new.psl. Any idea for loop in bash. The first name is common for the each name.ext and name.new.psl like perl customise.pl name.ext name.new.psl

Thinkhear · Accepted Answer · 2014-02-03 01:40:46Z

0

I guess the simplest form is

    for f in "*.ext"
    do                 
         customise.pl  $f.ext $f.ext.in      
    done

OUTPUT:

edited Feb 3, 2014 at 1:40

answered Feb 2, 2014 at 20:20

Thinkhear

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1 Comment

user3263699 Over a year ago

Hi thanks. I have thousands of two set of files one with name.ext and another files for the same name ending with name.new.psl, so for every name.ext there is a name.new.psl and now i have to pass this as argument to a script such as customise.pl name.ext name.new.psl. Any idea for loop in bash. The first name is common for the each name.ext and name.new.psl like perl customise.pl name.ext name.new.psl

BMW · Accepted Answer · 2014-02-03 04:37:57Z

0

another way.

ls *.ext |xargs -i customise.pl {} {}.in

answered Feb 3, 2014 at 4:37

BMW

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