ASP.NET MVC current request url (ajax call issue)

Question

I use popular technique "ReturnUrl". I pass current page url to server, do some staff and then i redirect user back to this url. For example, user posts comment and then get back to this url.

@using (Html.BeginForm("AddUserComment", "Home", new { returnUrl = HttpContext.Current.Request.RawUrl }, FormMethod.Post, new { enctype = "multipart/form-data" }))
{
...
}

BUT, when i load this form through ajax call, like this:

$.ajax({
        type: 'GET',
        url: '/Home/ShowUserCommentsBlock/',
        data: { entityType: entityType, entityId: entityId },
        cache: false,
        ...
    });

HttpContext.Current.Request.RawUrl returns ajax request url "/Home/ShowUserCommentsBlock?entityType=...", but i need current page url, where ajax request is called. What should I use instead of HttpContext object?

I get html-markup through ajax call, and then insert it in some div, like this: $('#div-usercommentsblock').html(data); — Sam Alekseev
– Sam Alekseev, Commented Feb 3, 2014 at 22:01

Sam Alekseev · Accepted Answer · 2014-02-04 01:49:42Z

6

Ok, i got this. We can use Request.UrlReferrer property for ajax requests to retrieve proper url, like this:

public ActionResult MyActionMethod()
{
            if (Request.IsAjaxRequest())
                ViewBag.ReturnUrl = HttpContext.Request.UrlReferrer.LocalPath;
            else
                ViewBag.ReturnUrl = HttpContext.Request.RawUrl;

            return View();
}

answered Feb 4, 2014 at 1:49

Sam Alekseev

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Comments

ramiramilu · Accepted Answer · 2014-02-04 07:59:45Z

You can pass current page url as one of the property in AJAX request.

Say your AJAX request is in this way -

        $.ajax({
            url: "@Url.Action("Submit")",
            type: "POST",
            data: {
                Url: '@HttpContext.Current.Request.Url'
            , entitytype: 'this is type'
            },
            error: function (response) {
                if (!response.Success)
                    alert("Server error.");
            },
            success: function (response) {
                alert(response);
            }
        });

Then add one more parameter to your POST action with name Url. and you will get the url you are passing in ajax request there.

enter image description here

Put the Url in the Viewbag and then assign it to the ReturnUrl.

ViewBag.Url = Url;

And assignment as below -

@using (Html.BeginForm("Comments", "Ajax", new { returnUrl = ViewBag.Url}, FormMethod.Post, new { enctype = "multipart/form-data" }))
{

}

Saffar · Accepted Answer · 2014-02-04 00:35:50Z

1

You need to send the page's url with the ajax request (with the help of some razor inside the javascript code) then at the controller store it in the Viewbag for example then use it instead of HttpContext.Current.Request.RawUrl

answered Feb 4, 2014 at 0:35

Saffar

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