PHP array_slice - how get original array without sliced items

Question

I have a PHP array with say 50 items in it. I then use array_slice to extract 12 items:

$extractItems = array_slice($rows,0,12);

I then use the $extractItems and this is fine.

The catch is I want to then write the remaining items (eg: $rows - $extractItems) to cache.

When I view $rows I can see array_slice doesn't remove the items. Just copies a section to a new array.

How would I best get a set of the items not 'array_sliced'?

thankyou :)

Phil · Accepted Answer · 2014-02-04 04:28:31Z

5

You could use array_splice instead. This would remove the first 12 items from $rows

$extractedItems = array_splice($rows, 0, 12);
// $rows now equals $rows - $extractedItems

A quick demo

php > $rows = [1,2,3,4,5,6];
php > $extractedItems = array_splice($rows, 0, 2);
php > var_dump($extractedItems, $rows);
array(2) {
  [0]=>
  int(1)
  [1]=>
  int(2)
}
array(4) {
  [0]=>
  int(3)
  [1]=>
  int(4)
  [2]=>
  int(5)
  [3]=>
  int(6)
}

answered Feb 4, 2014 at 4:28

Phil

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2 Comments

Ja͢ck Over a year ago

+1. I don't particularly like mutable arrays, but it can sometimes come in handy :)

Phil Over a year ago

@Jack Yeah, I considered that too but it seemed to match the OP's requirements

Ja͢ck · Accepted Answer · 2014-02-04 04:26:37Z

5

You can get the rest of the items by slicing from index 12 onwards:

array_slice($rows, 12);

This is similar to how substr($str, $index) works.

answered Feb 4, 2014 at 4:26

Ja͢ck

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