Convert C++ to Python (For Loop multiple assignment)

Question

Convert to python:

#include <iostream>
using namespace std;
int main(int argc, char** argv)
{
    for (int i = 0, j = i + 3; i < 100; ++i, j= i+3)
         cout << i << " j: " << j << endl;

    getchar();
    return 0;
}

I try:

for i in range(99):
    j = i + 3
    print i, " j: ", j

How to make it one for loop?

I mean I want to make the python program only 2 lines like the C++ reall tis — y2k
– y2k, Commented Jan 29, 2010 at 8:10
Like 0ne python FOR LOOP to do the same job the C++ for l00p d03s — y2k
– y2k, Commented Jan 29, 2010 at 8:10
Wow, if this use-case was any more real world, it would be the actual REAL WORLD — Ali Afshar
– Ali Afshar, Commented Jan 29, 2010 at 8:46
The C++ is way more than two lines. And the idea that code is better because there are fewer lines is misguided. — Lennart Regebro
– Lennart Regebro, Commented Jan 29, 2010 at 8:55

Prasoon Saurav · Accepted Answer · 2010-01-29 08:13:20Z

8

Just change 99 to 100

for i in range(100):
  j = i + 3
  print i, " j: ", j

Or

for i,j in [(i, i+3) for i in range(100)]:

edited Jan 29, 2010 at 8:13

answered Jan 29, 2010 at 8:06

Prasoon Saurav

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2 Comments

Prasoon Saurav Over a year ago

@jleedev: Your post was not there when I was typing. So why a downvote?

Ignacio Vazquez-Abrams Over a year ago

I would use a generator expression instead of a list comprehension there, were I to do it this way.

Josh Lee · Accepted Answer · 2010-01-29 08:08:08Z

6

These are identical except for the upper bound in the loop (98 vs 99). What is the question?

On one line (but please don't do this):

for i,j in [(i, i+3) for i in range(100)]:

answered Jan 29, 2010 at 8:08

Josh Lee

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Comments

Ignacio Vazquez-Abrams · Accepted Answer · 2010-01-29 08:06:24Z

5

Since j is always dependent on the value of i you may as well replace all instances of j with i + 3.

answered Jan 29, 2010 at 8:06

Ignacio Vazquez-Abrams

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Comments

Mizipzor · Accepted Answer · 2010-01-29 08:24:46Z

3

I dont get it, it is exactly one python for loop there. What is the question? Do you want the j declaration inside the loop declaration like in c++? Check Prasson'S answer for the closest python equivalent. But why have a j variable in the first place? j=i+3 seems to always be true, so why not this?

for i in range(100):
    print i, " j: ", i+3

answered Jan 29, 2010 at 8:24

Mizipzor

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Comments

Dyno Fu · Accepted Answer · 2010-01-29 08:29:27Z

1

for (i,j) in zip(range(100), range(3, 100+3)):

answered Jan 29, 2010 at 8:29

Dyno Fu

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Comments

Minh-Triet Pham Tran · Accepted Answer · 2012-02-06 14:22:51Z

0

for i in range(100):
    j = i + 3
    print i, "j:", j
raw_input()

C++: http://ideone.com/7Kdmk

Python: http://ideone.com/nATEP

edited Feb 6, 2012 at 14:22

answered Feb 6, 2012 at 14:13

Minh-Triet Pham Tran

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