I have tried most of the string and char format types and they are not working and I have no Idea why. Here is my code :
#include <iostream>
#include <stdio.h>
using namespace std;
int main(int argc, const char * argv[])
{
// insert code here...
string string2;
string string;
cout << "Hello, World!\n";
printf("Hi my name is Josh %s\n",string2);
scanf("%s",&string);
printf("hi %s",string);
}
What you're showing (scanf("%s",&string);) doesn't work (and never could, by e.g. giving different format specifiers)!
scanf() used with the %s format specifier requires a corresponding char* pointer referencing a raw char[] array to receive the read data in the parameter list. The std::string pointer you're passing in your example, doesn't provide automatic casting to the referred std::string instances internally managed char[] buffer that way though.
You could try to use &string.front() instead, but I wouldn't really recommend that, unless you're very sure what you're doing.
For c++ you should better use std::cin and
std::istream& operator>>(std::istream&, const std::string&)
instead:
std::cout << "Put in string value:" << std::endl;
std::string input;
std::cin >> input;
(xcode isn't relevant for your question BTW!)
You shouldn't mix std::cout with ::printf. Prefer to use the C++ Standard IO library over C functions from stdio.
Your code should look a little like this:
#include <iostream>
int main()
{
std::string string2;
std::string other_string;
std::cout << "Hello, World!\n";
std::cout << "Hi my name is Josh " << string2 << '\n';
std::cin >> other_string;
std::cout << "hi " << other_string;
}
scanf's%sformat specifier requires a matching character array parameter, not astd::string.std::getline(std::cin, string2);