I have one array and want split it in to two:
Now: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
New_1: [0, 2, 4, 6, 8]
New_2: [1, 3, 5, 7, 9]
So take the one element and skip the next element. Look easy but how can i do it with C#?
Thanks a lot
Add a comment
|
3 Answers
You can use linq, Enumerable.Where and get the array with elements that have even and odd indexes.
var New_1 = arr.Where((c,i) => i % 2 == 0).ToArray();
var New_2 = arr.Where((c,i) => i % 2 != 0).ToArray();
You can get the index of element of collection and apply condition to check if index is even or odd and get the arrays according.
Enumerable.Where Method (IEnumerable, Func) filters a sequence of values based on a predicate. Each element's index is used in the logic of the predicate function. The first argument of predicate represents the element to test. The second argument represents the zero-based index of the element within source, msdn
3 Comments
Brian Kintz
Don't forget
.ToArray()Brian Kintz
But he wants an array as the result.
Where() returns an IEnumerable
Adil
Thanks @elmugrat, so nice of you.
How about something like
int[] arr = new int[] {0, 1, 2, 3, 4, 5, 6, 7, 8, 9};
int[] arr1 = arr.Where((x, i) => i % 2 == 0).ToArray();
int[] arr2 = arr.Where((x, i) => i % 2 == 1).ToArray();
Comments
int[] arr = new int[] { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 };
int i = 0;
List<int[]> twoArr = arr.GroupBy(x => i++ % 2).Select(g => g.ToArray()).ToList();
3 Comments
Brian Kintz
This would work, but it doesn't give OP the result he wants (two arrays) and is (IMO) less readable than the
Where() version
L.B
@elmugrat If he wanted to split to 10, would you create 10 arrays manually. No I won't post a bad answer.
Brian Kintz
If he hadn't said "split it in to two", I'd agree with you, but since he only wants two, I think the improved readability is worth the extra line.