Compile C/C++ program via simple script

Question

I have multiple c source files. I would like to compile them via script. I know i can do this via makefile, but i prefer simple script instead.

I feel makefiles are too complex, so i'm looking for simple script to compile mulitple files and then create a shared library in Linux(GNU).

I know how to compile/build shared library using terminal so just want to run my command from simple script.

gcc -c -Wall tbl0.c tbl1.c tbl2.c 

gcc -shared -Wall -o libtbl.so tbl.c -I.
    -Wl,-z,defs -L. -lpthread -lm -ldl

Any help?

Having such script is fine for projects with only small source files, and only 2-4 of them. As soon as you begin hacking a slightly bigger project, any build system pays out as for the faster compile times. There is not only make, which indeed has an intriguing syntax, but many others as well. That's your search term. — Sebastian Mach
– Sebastian Mach, Commented Feb 18, 2014 at 9:20
@cup: That's what I wrote, only more generally. Anyways, currently, I prefer scons, too. QMake is pretty simple for small projects, cmake can be nice, too (but it can be pretty unnice, also). However, look for "build system" first. — Sebastian Mach
– Sebastian Mach, Commented Feb 18, 2014 at 9:21

Aman · Accepted Answer · 2014-02-18 09:14:52Z

1

Just copy paste your commands in a file, say x.sh.
Type chmod +x x.sh in the directory where x.sh resides.
Run x.sh by typing ./x.sh

apollo:~/test$ cat > x.sh   
gcc -c -Wall tbl0.c tbl1.c tbl2.c    

gcc -shared -Wall -o libtbl.so -I.    
    -Wl,-z,defs -L. -lpthread -lm -ldl  

apollo:~/test$ chmod +x x.sh   

apollo:~/test$ ./x.sh  #run

I will suggest that you stick with a Makefile. They may look complex initially, but are useful in the long run.

answered Feb 18, 2014 at 9:14

Aman

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jparthj Over a year ago

considering your advise, how could makefile add advantage over simple script file?

MLSC · Accepted Answer · 2014-02-18 10:02:24Z

1

Firstly:

chmod +x script.sh

then invoke it by saying:

./script.sh

your script should be:

#!/bin/bash
gcc -c -Wall tbl0.c tbl1.c tbl2.c 

gcc -shared -Wall -o libtbl.so tbl.c -I. -Wl,-z,defs -L. -lpthread -lm -ldl

Don't you forget input file in the second line?

edited Feb 18, 2014 at 10:02

answered Feb 18, 2014 at 9:27

MLSC

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3 Comments

MLSC Over a year ago

last line of my answer :D

MLSC Over a year ago

also #!/bin/bash at the top of script ;)

MLSC Over a year ago

@jparthj try to run it as root...or may be the problem relates to /sbin/ and such issues...may be flags in compiling should run from another path rather than #!/bin/bash

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