How to send a HTTP Header request rather than HTTP URL in Python

Question

I'm doing Oauth, and Linkedin needs me to send a "header" request instead of URL request (I have no idea what that means).

This is what someone says on Google:

If the library you are using isn't using HTTP headers for the authorization, you're not going to be able to access protected resources. Most OAuth libraries have an option that you can specify that will force it to use the header-based authorization.

Anyway, I specified it to headers! I know how to change it to headers. The only problem is...I don't know how to REQUEST stuff using the header method.

Before, without the header method:

url = oauth_request.to_url()
connection.request(oauth_request.http_method,url)
response = connection.getresponse()
s = response.read()

Now:

url = oauth_request.to_header()
connection.request(oauth_request.http_method,url)
response = connection.getresponse()
s = response.read()

But when I run it, I get this weird traceback.

File "/usr/lib/python2.6/httplib.py" in request
  874.             self._send_request(method, url, body, headers)
File "/usr/lib/python2.6/httplib.py" in _send_request
  891.         self.putrequest(method, url, **skips)
File "/usr/lib/python2.6/httplib.py" in putrequest
  807.                 if url.startswith('http'):

Exception Type: AttributeError at /g/
Exception Value: 'dict' object has no attribute 'startswith'

I solved it. I just put a 3rd argument , which is headers.

TIMEX
– TIMEX

2010-02-04 12:40:41 +00:00
Commented Feb 4, 2010 at 12:40 — TIMEX
– TIMEX, Commented Feb 4, 2010 at 12:40

Community · Accepted Answer · 2017-05-23 11:47:38Z

2

I don't know about this particular oauth library you are using, so I can't comment on that.

But,

It can be clearly identified from the traceback, that oauth_request.to_header() returns a dictionary and not a string, that httplib.py expects.
The way to set authentication credentials in http headers is as follows:

from this question

password_mgr = urllib2.HTTPPasswordMgrWithDefaultRealm()
top_level_url = "http://example.com/"
password_mgr.add_password(None, top_level_url, 'user', 'password')
handler = urllib2.HTTPBasicAuthHandler(password_mgr)
opener = urllib2.build_opener(urllib2.HTTPHandler, handler)
request = urllib2.Request(url)

Hope it helps!

edited May 23, 2017 at 11:47

CommunityBot

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answered Feb 4, 2010 at 12:13

lprsd

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joulesm · Accepted Answer · 2012-02-23 23:02:26Z

0

Your connection.request method can take in HTTP headers:

connection.request(method, url, body = body, headers={'Authorization':header})

For OAuth, there are a bunch of fields that 'header' has:

OAuth realm="http://api.linkedin.com", oauth_consumer_key="##########", oauth_nonce="############", oauth_signature="########", oauth_signature_method="HMAC-SHA1", oauth_timestamp="#########", oauth_token="#########", oauth_version="1.0"

All the #### are things you need to have or generate.

answered Feb 23, 2012 at 23:02

joulesm

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