There are several solutions you can take:
Disjunct FULL OUTER JOIN
SELECT
SUM(MYTABLE.ID) as theSum,
COUNT(DISTINCT MYTABLE.SOMEVALUE) as theCount,
COUNT(DISTINCT MYOTHERTABLE.SOMEOTHERVALUE) as theOtherCount
FROM MYTABLE
FULL OUTER JOIN MYOTHERTABLE ON 1=0
UNION two queries and leave the column for the other table null
SELECT
MAX(theSum) as theSum,
MAX(theCount) as theCount,
MAX(theOtherCount) AS theOtherCount
FROM (
SELECT
SUM(ID) as theSum,
COUNT(DISTINCT SOMEVALUE) as theCount,
NULL as theOtherCount
FROM MYTABLE
UNION ALL
SELECT
NULL,
NULL,
COUNT(DISTINCT SOMEOTHERVALUE)
FROM MYOTHERTABLE
)
Query 'with a query per column' against a single record table (eg RDB$DATABASE)
SELECT
(SELECT SUM(ID) FROM MYTABLE) as theSum,
(SELECT COUNT(DISTINCT SOMEVALUE) FROM MYTABLE) as theCount,
(SELECT COUNT(DISTINCT SOMEOTHERVALUE) FROM MYOTHERTABLE) as theOtherCount
FROM RDB$DATABASE
CTE per table + cross join
WITH query1 AS (
SELECT
SUM(ID) as theSum,
COUNT(DISTINCT SOMEVALUE) as theCount
FROM MYTABLE
),
query2 AS (
SELECT
COUNT(DISTINCT SOMEOTHERVALUE) as theOtherCount
FROM MYOTHERTABLE
)
SELECT
query1.theSum,
query1.theCount,
query2.theOtherCount
FROM query1
CROSS JOIN query2
There are probably some more solutions. You might want to ask yourself if it is worth the effort of coming up with a (convoluted, hard to understand) single query to get this data were two queries are sufficient, easier to understand and in the case of large datasets: two separate queries might be faster.