Java command line arguments through shell script

Question

when I try to command in command line it executes fine

$: /application/jre/bin/java -classpath /application/common/lib/apps.jar: ./updater.jar com.application.updatermain mobile

This executes perfectly fine and returns me the results whereas when I try putting this in a file called run.sh

If I create a run.sh as

/application/jre/bin/java -classpath /application/common/lib/apps.jar: ./updater.jar com.application.updatermain $@

and try to run it

./run.sh mobile

it acts weird

My java code:

if (args.length == 1) {
    if (args[0].equalsIgnoreCase("mobile") ) {
        updateDB = true;
    } else {
        System.out.println(" 1 :Usage: ./run.sh [mobile] "+ args[0]);
        return;
    }
}

It gives me the output

1 :Usage: ./run.sh [mobile] mobile

Am I missing anything here.

Thanks a lot

What do you gent when you print args (not only args[0])? — Trein
– Trein, Commented Mar 2, 2014 at 14:03
Why there is as space before "./updater.jar"? Should not it be part of the classpath? — robermann
– robermann, Commented Mar 2, 2014 at 14:06

Farvardin · Accepted Answer · 2014-03-02 14:14:11Z

1

it seems that some space add to argument. you must trim the arg[0] :

  if (args.length == 1) {
     if (args[0].trim().equalsIgnoreCase("mobile") ) {
        updateDB = true;
     }
  else {
        System.out.println(" 1 :Usage: ./run.sh [mobile] "+ args[0]);
        return;
     }
  }

answered Mar 2, 2014 at 14:14

Farvardin

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2 Comments

Mok Over a year ago

I am not getting any space, when I try to print it.

Farvardin Over a year ago

try this : System.out.println(" 1 :Usage: ./run.sh [mobile] #"+ args[0] + "#");

Farvardin · Accepted Answer · 2015-05-01 21:06:16Z

1

Remove the space before "./updater.jar"; the script "run.sh" should contain:

/application/jre/bin/java -classpath /application/common/lib/apps.jar:./updater.jar com.application.updatermain $@

edited May 1, 2015 at 21:06

Farvardin

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answered Mar 2, 2014 at 14:08

robermann

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