AngularJS $resource parameter name

Question

I'm working with a PhP interface. I must interact with this interface to save some data. For instance, to save a Customer, the PhP service wants the data through a POST request in this form

customer[customer_name] = "name of the customer"
customer[customer_code] = "code of the customer"
customer[customer_is_visible] = "whether or not the customer is visible"

I tried to create an AngularJS service to do that:

angular.module("app").factory("SaveCustomer", ["$resource", 
    function($resource){
        return $resource("/services/customers/post/", 
                            {
                                customer[customer_name]:'@name',
                                customer[customer_code]:'@code',
                                customer[customer_is_visible]:'@visibility',
                                dtsave:'true'
                            },
                            {
                                save: {
                                       method:'POST'
                                }
                            });
}]);

The problem is about the parameters name. Angular doesn't like the square bracket and it says: "Expected : but found [ in customer[custom ..." Can I achieve this task or do I have to modify the PhP interface to interact with? (note that the interface has not been created by me). Thank you.

EDIT: I call the service this way:

SaveCustomer.save({name:customerName, code:customerCode, visibility:customerIsVisible});

Can you post the line/s where you call to the $resource object ? — Roberto
– Roberto, Commented Mar 17, 2014 at 14:30
I edited the question. Take a look and thank you in advance. — superpuccio
– superpuccio, Commented Mar 17, 2014 at 14:38

Ascherer · Accepted Answer · 2014-03-17 14:43:45Z

1

Try turning customer into an object:

angular.module("app").factory("SaveCustomer", ["$resource", 
    function($resource){
        return $resource("/services/customers/post/", 
            {
                customer: { 
                    customer_name: '@name',
                    customer_code:'@code',
                    customer_is_visible:'@visibility'
                },
                dtsave:'true'
            },
            {
                save: {
                    method:'POST'
                }
            }
        );
    }
]);

edited Mar 17, 2014 at 14:43

answered Mar 17, 2014 at 14:31

Ascherer

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6 Comments

superpuccio Over a year ago

I need the array notation. The PhP interface would like to receive exactly customer[customer_name]='value', customer[customer_code]='code', customer[customer_is_visible]='value' ecc ecc as parameters"

Ascherer Over a year ago

thats how PHP will receive it. your browser will send it the way you are expecting it @superpuccio

superpuccio Over a year ago

How can I call the save function? Is this correct? SaveCustomer.save({name:customerName, code:customerCode, visibility:customerIsVisible});

Ascherer Over a year ago

that looks right, should be the same as before @superpuccio

superpuccio Over a year ago

Mmh...it doesn't seem to work. Have you ever verified that PhP receives data in the right "array" form passing parameters in your way? I suppose the answer is "yes" :)

|

Roberto · Accepted Answer · 2014-03-17 14:49:37Z

1

I think you don't need to define anything in default parameters in $resource object, this code should work (I think so)

angular.module("app").factory("SaveCustomer", ["$resource", 
    function($resource){
        return $resource("/services/customers/post/", 
            {
                dtsave:'true'
            },
            {
                save: {
                    method:'POST'
                }
            }
        );
    }
]);

And you can call it:

SaveCustomer.save({customer: {customer_name:customerName, customer_code:customerCode, customer_is_visible:customerIsVisible}});

answered Mar 17, 2014 at 14:49

Roberto

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1 Comment

Ascherer Over a year ago

i'd still keep them in there to declare what is required by the factory, otherwise a customer could not have one of these three fields, if not all of them

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