Using regex or Ruby functions to select elements after a certain string

Question

I have an array with a single element shown below:

array = [ 'c32860:x:3105:dputnam,kmathise,hhoang3,nhalvors,jchildre\n' ]

I want to create a new array that looks like this:

array2 = [ 'dputnum', 'kmathise', 'hhoang3', 'nhalvors', 'jchildre' ]

How would I accomplish this using Ruby and/or regex in a fairly clean way? I'm very new to programming and I did a bunch of ghetto things such as array-to-string-back-to-array conversions, .reverse.chomp.reverse shenanigans, and still could not end up with the result I wanted. Help appreciated!

inertialgradient · Accepted Answer · 2014-03-18 08:16:55Z

1

Try scan with a regexp:

array = [ 'c32860:x:3105:dputnam,kmathise,hhoang3,nhalvors,jchildre\n' ]
array = array.first.scan(/:?(\w+)[,\\n]/).flatten

p array
#=> ["dputnam", "kmathise", "hhoang3", "nhalvors", "jchildre"]

answered Mar 18, 2014 at 8:16

inertialgradient

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xdazz · Accepted Answer · 2014-03-18 08:16:38Z

0

Below will give you the expected result:

array2 = array[0].split(':').last.gsub(/\\n\Z/, '').split(',')

answered Mar 18, 2014 at 8:16

xdazz

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Arup Rakshit · Accepted Answer · 2014-03-18 08:31:53Z

0

I would do

array = [ 'c32860:x:3105:dputnam,kmathise,hhoang3,nhalvors,jchildre\n' ]
array[0].scan(/(?<=:)?\w+(?=[,\\n])/)
# => ["dputnam", "kmathise", "hhoang3", "nhalvors",'jchildre' ]

edited Mar 18, 2014 at 8:31

answered Mar 18, 2014 at 8:19

Arup Rakshit

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