Unable to convert binary string to integer despite using parseInt in java

Question

i want to get the integer i.e decimal number corresponding to the binary string nc. However this does not happen despite using parseInt(). for eg if nc="11000101" then edcode is also having the same value instead of giving me the decimal representation of nc. Can anyone please help

String codest="11010101";
char[] codear=codest.toCharArray();
codear[4]=codear[5];
String nc= new String(codear);
int edcode=Integer.parseInt(nc);

Try this: String codest="11010101"; int edcode=Integer.parseInt(codest, 2); — Heisenberg
– Heisenberg, Commented Mar 19, 2014 at 9:42

user2424380 · Accepted Answer · 2014-03-19 09:46:50Z

1

parseInt(String s, int radix) Parses the string argument as a signed integer in the radix specified by the second argument.

From here.

Try this:

int edcode=Integer.parseInt(nc, 2);

answered Mar 19, 2014 at 9:46

user2424380

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Varun · Accepted Answer · 2014-03-19 09:44:21Z

0

int edcode=Integer.parseInt(nc, 2); This will work

answered Mar 19, 2014 at 9:44

Varun

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4 Comments

Manika Over a year ago

thank you :) i would be grateful if you explain the logic behind it

Varun Over a year ago

JRE needs to know about the base of your number.

Varun Over a year ago

JRE needs to know about the base of your number. If number is in binary, we need to tell JRE that number is in binary format. For the same reason we passed 2 as binary is base 2. I hope this explains well. Please refer this for more details.docs.oracle.com/javase/7/docs/api/java/lang/…, int)

Varun Over a year ago

Can you please accept the answer. You may have to click right just below the answer.

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