I want to check the following condition, but it should be case insensitive. if [ "SPP" == $1 ] Is there anyway I can do it using regex.
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3 Answers
You can also do the following:
#!/bin/bash
myParam=`echo "$1" | tr 'a-z' 'A-Z'`
if [ "SPP" == "$myParam" ]; then
echo "Is the same"
else
echo "It is not the same"
fi
This script will automatically converts user input to uppercase before making any string comparison. By doing so, you will not have to use regex for case insensitive string comparison.
Hope it helps.
Comments
Better late than never...
If that's ksh93, use the ~(i:...) case-insensitive globbing sub-pattern:
if [[ $1 == *~(i:spp)* ]]; then
: matched.
fi
For ksh88 (also the ksh clones), use an intermediary variable typeset -u'd to force upper-case:
typeset -u tocheck=$1
if [[ $tocheck == *SPP* ]]; then
: matched
fi
Comments
You can use:
shopt -s nocasematch
For case insensitive matching in BASH.
Alternatively this should also work:
[[ "$1" == [sS][pP][pP] ]]
10 Comments
Shitu
if [ "[sS][pP][pP]" == "$1" ] then echo $1 else echo "hello" fi On running the above script by passing spp as parameter, I am not getting the desired output ./b.sh spp hello
anubhava
Did you try:
shopt -s nocasematch?anubhava
Ok I made a change as quotes are not needed. Try:
[ [sS][pP][pP] == "$1" ]Shitu
not sure but this is also not working: if [ [sS][pP][pP] == "$1" ] then echo "true" else echo "false" fi
anubhava
No both conditions are not same. Shell glob pattern works on right hand side only.
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