PHP Add array and loop to code

Question

I have a class which is working fine but I need to do multiple results.

Here is the current code:

$url = 'http://mydomain.com';
$keyword = 'somekeyword';

$RankChecker=new RankChecker(1,5);

$result=$RankChecker->find($url,$keyword);

if ($result!==false) {

    echo "Your website is found at page number  ".$result["page"].".";

}

What is the best way to get it to read multiple url's / keyword's ?

What's RankChecker?

gen_Eric
– gen_Eric

2014-04-03 15:51:08 +00:00
Commented Apr 3, 2014 at 15:51 — gen_Eric
– gen_Eric, Commented Apr 3, 2014 at 15:51
show what you have, and what you want (result)

user1954544
– user1954544

2014-04-03 15:52:36 +00:00
Commented Apr 3, 2014 at 15:52 — user1954544
– user1954544, Commented Apr 3, 2014 at 15:52

t.h3ads · Accepted Answer · 2014-04-03 15:53:43Z

1

Put the URLs and keywords into an array and loop through it:

$urls = array(
    'http://mydomain.com' => 'somekeyword',
    'http://myotherdomain.com' => 'someotherkeyword'
);

$RankChecker=new RankChecker(1,5);

foreach($urls as $url => $keyword) {
    $result=$RankChecker->find($url,$keyword);

    if ($result!==false) {

        echo "Website " . $url . " is found at page number  ".$result["page"].".";

    }
}

answered Apr 3, 2014 at 15:53

t.h3ads

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ôkio · Accepted Answer · 2014-04-03 15:54:02Z

1

Using an array :

<?php

$websites[1] = array('url' => 'http://mydomain.com', 'keyword' => 'somekeyword');
$websites[2] = array('url' => 'http://mydomain2.com', 'keyword' => 'somekeyword2');
$websites[3] = array('url' => 'http://mydomain3.com', 'keyword' => 'somekeyword3');
// etc...

foreach ($websites as $val) 
{
    $RankChecker=new RankChecker(1,5);

    $result=$RankChecker->find($val['url'], $val['keyword']);

    if ($result!==false) {

        echo "Your website is found at page number  ".$result["page"].".";

    }   
}

answered Apr 3, 2014 at 15:54

ôkio

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