Run a python script from another python script using IF name == "main" statement

Question

I have a script LCP_02.py with the if statement:

if __name__ == "__testcase__" or __name__ == "__main__":

    ask_costsurfacepath_path()
    ask_outputpath_path()
    CostSurfacefn = config.costsurfacepath
    startCoord = (config.startX,config.startY)
    stopCoord = (config.stopX,config.stopY)
    outputPathfn = config.outputpath
    main(CostSurfacefn,outputPathfn,startCoord,stopCoord)

when I run testcase.py (below) in the shell, it doesn't run the LCP_02 script:

import config
import LCP_02

if __name__ == "__main__":
    config.startX = 356254.432
    config.startY = 5325191.299
    config.stopX = 346200.101
    config.stopY = 5301688.499
    LCP_02

All the functions in LCP_02 have print statements (as a visual). But when running testcase.py, they are not printed. The program starts, waits around 2 seconds, and then shows the >>> in the shell.

Martijn Pieters · Accepted Answer · 2014-04-04 07:20:40Z

1

There are two reasons it doesn't work:

You imported LCP_02, so the __name__ value in that module is set to 'LCP_02', not '__main__' or '__testcase__'. The name is never based on whatever imported the module.
Just referencing LCP_02 on a line won't 'invoke' that module; if the guarded code was going to run, it would have done so when importing.

Use a function in LCP_02 instead:

def run_test():
    ask_costsurfacepath_path()
    ask_outputpath_path()
    CostSurfacefn = config.costsurfacepath
    startCoord = (config.startX,config.startY)
    stopCoord = (config.stopX,config.stopY)
    outputPathfn = config.outputpath
    main(CostSurfacefn,outputPathfn,startCoord,stopCoord)

if __name__ == "__main__":
    run_test()

and call that function from your testcase.py module:

LCP_02.run_test()

answered Apr 4, 2014 at 7:20

Martijn Pieters

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