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I have a URL in my app.js containing routes. lets say the url is:

/api/:opt1/:opt2/:opt3/users

I want that my url will work in any case, i should able to ignore the optional parameters (opt1, opt2 or opt3, may be all or few). How can I achieve this.

Is there any way that I can call $location.path('/users'), and I can specify also what are the values of the optional parameters?

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Optional route parameters are marked with ?, like this:

`/users/:id?`

Then this route matches both /users and /users/1 paths

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3 Comments

With Angular 1.3.4 I'm getting this error when I try that: Error: Invalid parameter name '' in pattern '/users/:id?'
Not working for me...Do i need some module/library?.. I am using ui-router? I also tried adding ngRoute but still no result
@Sami this is not for ui-router. In ui-router you shall use query string /users?id

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