how to overcome integer overflow in fortran 90?

Question

hi i am having some problem with integer over flow in fortran 90. The maximum range of integer number is 10 digits.but, I want to deal with integer of the range 1E13. So what is the way of avoiding this?

innoSPG · Accepted Answer · 2014-04-18 20:20:05Z

2

define your variable as

   integer(kind=8) :: intVar

To have a portable code, use the function selected_int_kind. In your case

   integer, parameter, k14 = selected_int_kind(14)
   integer(kind=k14) :: intVar

selected_int_kind(r) returns the kind value of the smallest integer type that can represent all values ranging from -10^r (exclusive) to 10^r (exclusive, that is why I used 14). For more details on selected_int_kind, See http://gcc.gnu.org/onlinedocs/gfortran/SELECTED_005fINT_005fKIND.html. Keep it mind that selected_int_kind might return -1, ff there is no integer kind that accommodates the chosen range.

edited Apr 18, 2014 at 20:20

answered Apr 18, 2014 at 18:38

innoSPG

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