Python regex multiple matching groups

Question

I am using a small utility to find the type a file under Windows.

TrID/32 - File Identifier v2.10 - (C) 2003-11 
By M.Pontello Definitions found:  5295  Analyzing... 

Collecting data from file: april_error.wmv

94.1% (.WMV/WMA) Windows Media (generic) (16018/6)
 5.8% (.CAT) Microsoft Security Catalog (1000/1)

In Python, how can I capture the (.WMV/WMA) cause it seems that I currently get a wrong matching group. For instance re.search('\((.*?)\)', stdout).group(1) returns 'C'

Thanks in advance.

Do you only want to capture this: (.WMV/WMA) ?

Pedro Lobito
– Pedro Lobito

2014-04-23 09:06:27 +00:00
Commented Apr 23, 2014 at 9:06 — Pedro Lobito
– Pedro Lobito, Commented Apr 23, 2014 at 9:06

sshashank124 · Accepted Answer · 2014-04-23 09:02:14Z

2

Try using findall instead:

a = re.findall('\((.*?)\)', stdout)

>>> print a
['C','.WMV/WMA','generic','16018/6','.CAT','1000/1']

>>> print a[1]
.WMV/WMA

Or as @tobias_k suggested, do the following to only capture the file extension matches:

a = re.findall('\((\..*?)\)', stdout)

>>> print a
['.WMV/WMA', '.CAT']

answered Apr 23, 2014 at 9:02

sshashank124

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3 Comments

tobias_k Over a year ago

+1 Maybe add a \. to find only the groups with actual file extensions.

stratis Over a year ago

@sshashank124 I believe you've got to cut out the .group part cause I get the following error: AttributeError: 'list' object has no attribute 'group'

stratis Over a year ago

@sshashank124 Yes. It does. Thank you. I'll accept your answer in 5'.

Pedro Lobito · Accepted Answer · 2014-04-23 09:08:47Z

1

Based on your comment above, this is what you need:

match = re.search(r"% \([a-z.]+/[a-z.]+\)", subject, re.IGNORECASE)

answered Apr 23, 2014 at 9:08

Pedro Lobito

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