accessing structure variable through pointer

Question

#include<stdio.h>
#include<string.h>
#include<malloc.h>
typedef struct male_node
{
    int mv1,mv2,mv3;
}male;

typedef struct movie_name
{
    char mvnm[20];
    struct male *ml;
}movie;

main()
{
    movie mov1;
    mov1.ml=(male*)malloc(sizeof(male));
    mov1.(*ml).mv1=1;//ERROR
    mov1.ml->mv1=1; //ERROR
}

How to access the mv1 variable through mov1 and ml I tried to access mv1 through ml which is a pointer to a structure which is again a structure variable but it shows error.

I know that you don't have to put an int in front of main but it hurts my heart when I see it is missing. — user21926
– user21926, Commented Apr 29, 2014 at 18:42

Caleb · Accepted Answer · 2014-04-29 18:42:57Z

4

This looks wrong:

struct male *ml;

You've used typedef to define male as struct male_node, so it doesn't make sense to say struct male. Instead, try this:

typedef struct movie_name
{
    char mvnm[20];
    male *ml;
} movie;

That should fix your problem, and you should be able to do this:

mov1.ml->mv1=1;

answered Apr 29, 2014 at 18:42

Caleb

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2 Comments

user971089 Over a year ago

Thank You. Actually I did not noticed that. It now works fine.

BLUEPIXY Over a year ago

and mov1.(*ml).mv1=1; to (*mov1.ml).mv1=1;

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