I would like the following if statement to alert 'yes' if 'featured' is in array, regardless of whether it is uppercase or lowercase.
I'm also not very familiar with Regular Expressions, so perhaps my regular expression is wrong..
var myArray = ["featured", "foo", "bar"];
if( $.inArray(/featured/i, myArray) > -1 ){
alert('yes!');
}
I don't think $.inArray supports regular expressions, but you could make your own function that does.
$.inArrayRegEx = function(regex, array, start) {
if (!array) return -1;
start = start || 0;
for (var i = start; i < array.length; i++) {
if (regex.test(array[i])) {
return i;
}
}
return -1;
};
Working demo: http://jsfiddle.net/jfriend00/H4Y9A/
You could even override the existing inArray to make it "optionally" support regular expressions while still retaining its regular functionality:
(function() {
var originalInArray = $.inArray;
$.inArray = function(regex, array, start) {
if (!array) return -1;
start = start || 0;
if (Object.prototype.toString.call(regex) === "[object RegExp]") {
for (var i = start; i < array.length; i++) {
if (regex.test(array[i])) {
return i;
}
}
return -1;
} else {
return originalInArray.apply(this, arguments);
}
};
})();
Working demo: http://jsfiddle.net/jfriend00/3sK7U/
Note: the one thing you would lose with this override is the ability to find a regular expression object itself in an array.
$.inArray().An array is not a string, but you can make it a string, by using toString
if(/featured/.test(myArray.toString())){
alert('yes!');
}
No, I don't think so.
This is how I would to it, using ($.each and match()):
var myArray = ["featured", "foo", "bar"];
$.each(myArray,function(index,value){
if(value.match(/featured/i) !== null){
alert("Yes!");
return false;
}
});
on JSFIDDLE: http://jsfiddle.net/QGtZU/
Version using Javascript exec and forEach. It achieves the same but does not use inArray.
var myArray = ["featured", "foo", "bar"];
var exp = /featured/i;
myArray.forEach( function(value){
if( exp.exec(value) ){
alert("yes");
}
} );
