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Trying to figure out a reg ex, for example, this string:

*/30 * * * * http://www.domain.com/wp-cron.php?doing_wp_cron >/dev/null 2>&1

I need to capture the beginning */30 * * * * and ending value of /wp-cron.php?doing_wp_cron >/dev/null 2>&1, but it doesn't matter what is in between those values.

Also, the beginning part of: */30 * * * *, can also sometimes be these values:

0 * * * * or 0 0 * * *

In which case, I'll need a regex for this as well, or, if one can do them all, that would be great!! The beginning part is actually within a string variable if that matters. Which can be any of the following values above.

How can I do this?

So far, I have something like this: ^\*\/30 [\*].+\s[*4]

But my regex skills are slim to none and this only matches the beginning... need to match the end, of if there is a way to put the site_url() into the regex also, and we can match the entire line, which would be preferred.

EDIT

Ok, so there is a variable like this: site_url(), this will return a WordPress Blog site URL in a string, like this: http://www.domain.com.

Now, there is another variable called, $updateinterval, this will contain any of the string values: */30 * * * *, or 0 * * * *, or 0 0 * * *

Now, I build a string from these variables like so:

$cron_job = $updateinterval . ' ' . site_url() . '/wp-cron.php?doing_wp_cron >/dev/null 2>&1';

It than uses this to insert a Cron Job in PHP (supposedly). However, in order to remove the cron job (thus cleaning up if there is no need for it anymore), I need to use a regex to find the line for the cron job, and edit the file needed to remove it.

Now, I can get the FULL string of what is set within $cron_job at anytime, even what was set previously. So, in that case, if it is possible to match the entire string $cron_job with a regex, that is what would be best. But, how to use these variables $updateinterval and site_url() within a regex?

So, I have a class that uses preg_grep to remove the line where the cron job is being set. But how to use it to match all of the possible values from the variables? Or just grab the start and end constants? Whichever way is fine with me.

* RE-EDIT* So, for example, it needs to search within a file, and if any of these are found (REGEX), than it is a match and will be removed by the cron job:

// let's just say that site_url() resolves to: http://www.domain.com for the sake of this. This will be different on a per site basis ofcourse.

*/30 * * * * http://www.domain.com/wp-cron.php?doing_wp_cron >/dev/null 2>&1
0 * * * * http://www.domain.com/wp-cron.php?doing_wp_cron >/dev/null 2>&1
0 0 * * * http://www.domain.com/wp-cron.php?doing_wp_cron >/dev/null 2>&1

Anything else should FAIL, anything at all besides the 3 strings above should fail! So the regex should only match the 3 given strings above and that's it. That is to say, whatever site_url() is, it should add it to the regex, if possible.

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18
  • How about splitting by spaces? Commented May 12, 2014 at 8:44
  • I don't know, doesn't seem right... don't want to interfere with other strings Commented May 12, 2014 at 8:49
  • Why is this question voted to be closed? It is a valid question is it not? Commented May 12, 2014 at 8:58
  • 2
    @SolomonClosson Also see, if something similar this example would fit your needs then. Commented May 12, 2014 at 12:19
  • 1
    haha :) great a solution found finally, happy Commented May 12, 2014 at 12:22

2 Answers 2

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2

Going on your third re-edit, if you want to be that specific it's really quite easy:

^((\d|\*(/\d{1,2})?)\s){5}http://www.\S+/.+doing_wp_cron\s>/dev/null\s2>&1$

but it really depends on how specific you want to get, I'd replace most of that with \S+ groups but it's up to you, (for example the /dev/null and the 2>&1 parts) but I made it as restrictive as possible given your requirements. the following are matched

*/30 * * * * http://www.domain.com/wp-cron.php?doing_wp_cron >/dev/null 2>&1
0 * * * * http://www.domain.com/wp-cron.php?doing_wp_cron >/dev/null 2>&1
0 0 * * * http://www.domain.com/wp-cron.php?doing_wp_cron >/dev/null 2>&1

see here

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3 Comments

Wow, awesome, is it possible to add in the site_url() variable into the regex? Like the string that gets returned from this function?
sure, just replace http://www.\S+ part with site_url() and be sure to escape it.
@SolomonClosson no worries, his is a good answer, I upvoted it too. :)
1

Well, here is my approach then:

$pattern = '~^(?:\*/30\s\*|0\s[*0])(?:\s\*){3}\s'.preg_quote(site_url(),"~").'~';

The first part should match only the cases: */30 * * * *, 0 * * * *, 0 0 * * *

Using a (?: non-capturing group for the alternation and (?:\s\*){3} to match * * *.

Followed by whatever your site_url() outputs. So, just match it:

$arr_input = array(
"*/30 * * * * http://www.testing.com/wp-cron.php?doing_wp_cron >/dev/null 2>&1",
"0 * * * * http://www.domain.com/bar.php?doing_wp_cron >/dev/null 2>&1",
"0 * * * * http://www.a.test/b.php?doing_wp_cron >/dev/null 2>&1",
"*/30 * * * * http://www.domain.com/wp-cron.php?doing_wp_cron >/dev/null 2>&1",
"0 * * * * http://www.domain.com/wp-cron.php?doing_wp_cron >/dev/null 2>&1",
"0 0 * * * http://www.domain.com/wp-cron.php?doing_wp_cron >/dev/null 2>&1");

foreach($arr_input AS $v)
{
  if(preg_match($pattern, $v)) {
    echo "MATCH: ".$v."\n";
  } else {
    echo "FAIL: ".$v."\n";
  }
}

Test, Also see SO Regex FAQ

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3 Comments

OMG, now it needs to be like this: 0,30 * * * * wget -O /dev/null http://www.testing.com/wp-cron.php?doing_wp_cron >/dev/null 2>&1, and 0 * * * * wget -O /dev/null http://www.testing.com/wp-cron.php?doing_wp_cron >/dev/null 2>&1 and 0 0 * * * wget -O /dev/null http://www.testing.com/wp-cron.php?doing_wp_cron >/dev/null 2>&1 instead. Can you help with this please?
So, just need to add in wget -O /dev/null before the URL.
Nevermind, I figured it out: $pattern = '~^(?:0,30\s\*|0\s[*0])(?:\s\*){3}\s(?:wget\s\-O\s\/dev\/null)\s'.preg_quote(site_url(),"~").'~'; Cheers :)

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