The following does not compile,
def echo(sep: String =" ", s: String*) = s.mkString(sep)
The desired function signature would have a first argument with default value and the rest, any number of strings.
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2So how would you distinguish between a defaulted first arg followed by multiple args, and a specified first arg followed by multiple args ?Brian Agnew– Brian Agnew2014-05-27 11:31:42 +00:00Commented May 27, 2014 at 11:31
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1 Answer
This is problematic.
Consider this:
echo("a", "b", "c") : is "a" now the seperator or does it belong to s? This cannot be decided by the compiler, since both would work.
A workaround can be to use multiple parameter lists.
def echo(sep: String =" ")(s: String*) = s.mkString(sep)
Now you can use:
echo()("a", "b", "c") //"a b c"
echo("a")("b", "c") //"bac"
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